Java, Convert instance of Class to HashMap

Question

If I have class like this:

class MyObject {
    public int myInt;
    public String myString;
}

Is it possible to convert instance of this class to HashMap without implementing converting code?

MyObject obj = new MyObject();
obj.myInt = 1; obj.myString = "string";
HashMap<String, Object> hs = convert(obj);

hs.getInt("myInt"); // returns 1
hs.getString("myString"); // returns "string"

Does Java provide that kind of solution, or I need to implement convert by myself?

My Class has more than 50 fields and writing converter for each field is not so good idea.

Answer 1

With jackson library this is also possible

MyObject obj = new MyObject();
obj.myInt = 1;
obj.myString = "1";
ObjectMapper mapObject = new ObjectMapper();
Map < String, Object > mapObj = mapObject.convertValue(obj, Map.class);

Answer 2

You can use reflection for implementing this behavior. You can get all fields of the class you want to convert to map iterate over this fields and take the name of each field as key of the map. This will result in a map from String to object.

Map<String, Object> myObjectAsDict = new HashMap<>();    
Field[] allFields = SomeClass.class.getDeclaredFields();
    for (Field field : allFields) {
        Class<?> targetType = field.getType();
        Object objectValue = targetType.newInstance();
        Object value = field.get(objectValue);
        myObjectAsDict.put(field.getName(), value);
    }
}

Answer 3

Something like that will do the trick:

MyObject obj = new MyObject();
obj.myInt = 1; obj.myString = "string";
Map<String, Object> map = new HashMap<>();
// Use MyObject.class.getFields() instead of getDeclaredFields()
// If you are interested in public fields only
for (Field field : MyObject.class.getDeclaredFields()) {
    // Skip this if you intend to access to public fields only
    if (!field.isAccessible()) {
        field.setAccessible(true);
    }
    map.put(field.getName(), field.get(obj));
}
System.out.println(map);

Output:

{myString=string, myInt=1}