Java 8 lambda get and remove element from list

Question

Given a list of elements, I want to get the element with a given property and remove it from the list. The best solution I found is:

ProducerDTO p = producersProcedureActive                 .stream()                 .filter(producer -> producer.getPod().equals(pod))                 .findFirst()                 .get(); producersProcedureActive.remove(p); 

Is it possible to combine get and remove in a lambda expression?

Answer 1

To Remove element from the list

objectA.removeIf(x -> conditions); 

eg:

objectA.removeIf(x -> blockedWorkerIds.contains(x));  List<String> str1 = new ArrayList<String>(); str1.add("A"); str1.add("B"); str1.add("C"); str1.add("D");  List<String> str2 = new ArrayList<String>(); str2.add("D"); str2.add("E");  str1.removeIf(x -> str2.contains(x));   str1.forEach(System.out::println); 

OUTPUT: A B C

Answer 2

Although the thread is quite old, still thought to provide solution - using Java8.

Make the use of removeIf function. Time complexity is O(n)

producersProcedureActive.removeIf(producer -> producer.getPod().equals(pod)); 

API reference: removeIf docs

Assumption: producersProcedureActive is a List

NOTE: With this approach you won't be able to get the hold of the deleted item.