I'm trying to split a list into a list of list where each list has a maximum size of 4.
I would like to know how this is possible to do using lambdas.
Currently the way I'm doing it is as follow:
List<List<Object>> listOfList = new ArrayList<>();
final int MAX_ROW_LENGTH = 4;
int startIndex =0;
while(startIndex <= listToSplit.size() )
{
int endIndex = ( ( startIndex+MAX_ROW_LENGTH ) < listToSplit.size() ) ? startIndex+MAX_ROW_LENGTH : listToSplit.size();
listOfList.add(new ArrayList<>(listToSplit.subList(startIndex, endIndex)));
startIndex = startIndex+MAX_ROW_LENGTH;
}
UPDATE
It seems that there isn't a simple way to use lambdas to split lists. While all of the answers are much appreciated, they're also a wonderful example of when lambdas do not simplify things.
Given below is the simplest way to create a list of lists in Java: For String: List<List<String>> listOfLists = new ArrayList<>(); That's it.
We can look at the “List of Lists” data structure as a two-dimensional matrix. So, if we want to group a number of List<T> objects, we have two options: Array-based: List<T>[]
If you REALLY need a lambda it can be done like this. Otherwise the previous answers are better.
List<List<Object>> lists = new ArrayList<>();
AtomicInteger counter = new AtomicInteger();
final int MAX_ROW_LENGTH = 4;
listToSplit.forEach(pO -> {
if(counter.getAndIncrement() % MAX_ROW_LENGTH == 0) {
lists.add(new ArrayList<>());
}
lists.get(lists.size()-1).add(pO);
});
Try this approach:
static <T> List<List<T>> listSplitter(List<T> incoming, int size) {
// add validation if needed
return incoming.stream()
.collect(Collector.of(
ArrayList::new,
(accumulator, item) -> {
if(accumulator.isEmpty()) {
accumulator.add(new ArrayList<>(singletonList(item)));
} else {
List<T> last = accumulator.get(accumulator.size() - 1);
if(last.size() == size) {
accumulator.add(new ArrayList<>(singletonList(item)));
} else {
last.add(item);
}
}
},
(li1, li2) -> {
li1.addAll(li2);
return li1;
}
));
}
System.out.println(
listSplitter(
Arrays.asList(0, 1, 2, 3, 4, 5, 6, 7, 8, 9),
4
)
);
Also note that this code could be optimized, instead of:
new ArrayList<>(Collections.singletonList(item))
use this one:
List<List<T>> newList = new ArrayList<>(size);
newList.add(item);
return newList;
Surely the below is sufficient
final List<List<Object>> listOfList = new ArrayList<>(
listToSplit.stream()
.collect(Collectors.groupingBy(el -> listToSplit.indexOf(el) / MAX_ROW_LENGTH))
.values()
);
Stream it, collect with a grouping: this gives a Map of Object -> List, pull the values of the map and pass directly into whatever constructor (map.values() gives a Collection not a List).
Perhaps you can use something like that
BiFunction<List,Integer,List> splitter= (list2, count)->{
//temporary list of lists
List<List> listOfLists=new ArrayList<>();
//helper implicit recursive function
BiConsumer<Integer,BiConsumer> splitterHelper = (offset, func) -> {
if(list2.size()> offset+count){
listOfLists.add(list2.subList(offset,offset+count));
//implicit self call
func.accept(offset+count,func);
}
else if(list2.size()>offset){
listOfLists.add(list2.subList(offset,list2.size()));
//implicit self call
func.accept(offset+count,func);
}
};
//pass self reference
splitterHelper.accept(0,splitterHelper);
return listOfLists;
};
Usage example
List<Integer> list=new ArrayList<Integer>(){{
add(1);
add(2);
add(3);
add(4);
add(5);
add(6);
add(7);
add(8);
add(8);
}};
//calling splitter function
List listOfLists = splitter.apply(list, 3 /*max sublist size*/);
System.out.println(listOfLists);
And as a result we have
[[1, 2, 3], [4, 5, 6], [7, 8, 8]]
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