Java 8 Best way to build an IntStream from input

Question

I have as input (STDIN)

0 0 1 2 1

and I want to create a stream from it the simplest possible way.

I did create a stream by reading one by one each integer and storing them into an ArrayList. From there I just had to use .stream().reduce() to make it work.

What I want is a possible way to create a stream directly from the input

I tried to adapt this code :

ByteArrayInputStream inputStream = new ByteArrayInputStream(bytes);
IntStream is2 = IntStream.generate(inputStream::read).limit(inputStream.available());

by using a DataInputStream and the readInt() method

DataInputStream dis = new DataInputStream(System.in);
IntStream is2 = IntStream.generate(dis::readInt).limit(5);//later : dis.available() instead of 5

but it doesn't work I've incompatible thrown types IOException on the generate function.

Can I do it ? Or is there another way to transform an input into a stream

my reduce function to be applied is

reduce( (x , y) -> x ^ y) 

I've already done this on ArrayList quite easily by doing

list.stream().reduce( (x , y) -> x ^ y);

SOLUTION

I've tried using this with a scanner to do the job but unsuccessfully and now I managed to make it work

Scanner sc = new Scanner(System.in);
    int oi = Stream.of(sc.nextLine().split(" "))
                    .mapToInt(Integer::parseInt)
                    .reduce( (x , y) -> x ^ y).getAsInt();
    System.out.println(oi);

I don't understand why it didn't work at the beginning

Answer 1

SOLUTION

Scanner sc = new Scanner(System.in);
    int oi = Stream.of(sc.nextLine().split(" "))
                    .mapToInt(Integer::parseInt)
                    .reduce( (x , y) -> x ^ y).getAsInt();
    System.out.println(oi);