Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

It is possible to get total storage capacity?

i know how to get free capacity on internal memory and on external storage.

But i want to know max capacity of internal memory and max capacity of external storage, but i can't find any info about it on google

it is possible to achieve it?

thanks

like image 664
Pableras84 Avatar asked Jan 25 '13 23:01

Pableras84


1 Answers

Some new methods were introduced in API 18. This is the code I used to get total storage (internal + external).

private static final long KILOBYTE = 1024;

StatFs internalStatFs = new StatFs( Environment.getRootDirectory().getAbsolutePath() );
long internalTotal;
long internalFree;

StatFs externalStatFs = new StatFs( Environment.getExternalStorageDirectory().getAbsolutePath() );
long externalTotal;
long externalFree;

if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.JELLY_BEAN_MR2) {
    internalTotal = ( internalStatFs.getBlockCountLong() * internalStatFs.getBlockSizeLong() ) / ( KILOBYTE * KILOBYTE );
    internalFree = ( internalStatFs.getAvailableBlocksLong() * internalStatFs.getBlockSizeLong() ) / ( KILOBYTE * KILOBYTE );
    externalTotal = ( externalStatFs.getBlockCountLong() * externalStatFs.getBlockSizeLong() ) / ( KILOBYTE * KILOBYTE );
    externalFree = ( externalStatFs.getAvailableBlocksLong() * externalStatFs.getBlockSizeLong() ) / ( KILOBYTE * KILOBYTE );
}
else {
    internalTotal = ( (long) internalStatFs.getBlockCount() * (long) internalStatFs.getBlockSize() ) / ( KILOBYTE * KILOBYTE );
    internalFree = ( (long) internalStatFs.getAvailableBlocks() * (long) internalStatFs.getBlockSize() ) / ( KILOBYTE * KILOBYTE );
    externalTotal = ( (long) externalStatFs.getBlockCount() * (long) externalStatFs.getBlockSize() ) / ( KILOBYTE * KILOBYTE );
    externalFree = ( (long) externalStatFs.getAvailableBlocks() * (long) externalStatFs.getBlockSize() ) / ( KILOBYTE * KILOBYTE );
}

long total = internalTotal + externalTotal;
long free = internalFree + externalFree;
long used = total - free;
like image 106
James McCracken Avatar answered Sep 28 '22 03:09

James McCracken