The intention was to implement some sort of plugin framework, where plugins are subclasses (i.e. B) of the same base class (i.e. A). The base class is loaded with standard import, whereas subclasses are loaded with imp.load_module() from the path of a well-known package (i.e. pkg).
pkg/
__init__.py
mod1.py
class A
mod2.py
class B(pkg.mod1.A)
This worked fine with real subclasses, i.e.,
# test_1.py
import pkg
from pkg import mod1
import imp
tup = imp.find_module('mod2', pkg.__path__)
mod2 = imp.load_module('mod2', tup[0], tup[1], tup[2])
print(issubclass(mod2.B, mod1.A)) # True
But the problem came when testing the base class itself,
# test_2.py
import pkg
from pkg import mod1
import imp
tup = imp.find_module('mod1', pkg.__path__)
mod0 = imp.load_module('mod1', tup[0], tup[1], tup[2])
print(issubclass(mod0.A, mod1.A)) # False
But mod0.A and mod1.A are actually the same class from the same file (pkg/mod1.py).
This issue appears in both python 2.7 and 3.2.
Now the question is two-fold, a) Is it an expected feature or a bug of issubclass(), and b) How to get rid of this without changing contents of pkg?
They aren't the same class. They were created with the same code, but since you executed that code twice (once in the import and once in load_module) you get two different class objects. issubclass
is comparing the identities of the class objects and they're different.
Edit: since you can't rely on issubclass
, one possible alternative is to create a unique attribute on the base class that will be inherited by the derived classes. This attribute will exist on copies of the class as well. You can then test for the attribute.
class A:
isA = True
class B(A):
pass
class C:
pass
def isA(aclass):
try:
return aclass.isA
except AttributeError:
return False
print isA(A)
True
print isA(B)
True
print isA(C)
False
Since I spent some time fiddling with this, I thought I would share my solution:
import inspect
...
def inherits_from(child, parent_name):
if inspect.isclass(child):
if parent_name in [c.__name__ for c in inspect.getmro(child)[1:]]:
return True
return False
print inherits_from(possible_child_class, 'parent_class')
#True
Of course this only really checks that the child class inherits from a class CALLED parent_class
, but for my purpose (and most I suspect) that's fine.
Note: this returns false if possible_child_class
is an instance of parent_class due to the [1:]
.
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