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Is unaligned access in Cortex-M4 atomic?

In the ARM documentation, it mentions that

The Cortex-M4 processor supports ARMv7 unaligned accesses, and performs all accesses as single, unaligned accesses. They are converted into two or more aligned accesses by the DCode and System bus interfaces.

It's not clear to me if this means the data access is atomic to the programmer or not. Then I found a StackOverflow comment interpreting the documentation as:

Actually some ARM processors like the Cortex-M3 support unaligned access in HW, so even an unaligned read/write is atomic. The access may span multiple bus cycles to memory, but there is no opportunity for another instruction to jump in between, so it is atomic to the programmer.

However, I looked around some more and found claims that contradicts the previous claim:

Another one is the fact that on cores beginning ARMv6 and later, in order for the hardware to “fix-up” an unaligned access, it splits it up into multiple smaller, byte loads. However, these are not atomic!.

So, who do I believe? For some context, I have setters/getters for each element in a packed struct in my project. In other words, some struct elements may be unaligned. I was wondering if accessing the struct elements will always be guaranteed to be atomic on Cortex-M4. If it's not, I am thinking I will have to enable/disable interrupts manually or add in some mutex, but I'd rather not if ARM Cortex M4 can just guarantee the data accesses to be atomic.

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Ken Lin Avatar asked Nov 30 '19 03:11

Ken Lin


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1 Answers

Nope, it isn't.

See section A3.5.3 at https://static.docs.arm.com/ddi0403/eb/DDI0403E_B_armv7m_arm.pdf

Quote from the ARMv7-M reference manual

In ARMv7-M, the single-copy atomic processor accesses are:
• All byte accesses.
• All halfword accesses to halfword-aligned locations.
• All word accesses to word-aligned locations

So, if you are copying a uint32 that isn't aligned to a 32-bit boundary (which is allowed in v7-M), the copy isn't atomic.

Also quoting,

When an access is not single-copy atomic, it is executed as a sequence of smaller accesses,
each of which is single-copy atomic, at least at the byte level.
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R S Avatar answered Oct 04 '22 23:10

R S