Sorry for the basic question, but I'm having trouble finding the right thing to google.
#include <iostream>
#include <string>
using namespace std;
class C {
public:
C(int n) {
x = new int(n);
}
~C( ) {
delete x;
}
int getX() {return *x;}
private:
int* x;
};
void main( ) {
C obj1 = C(3);
obj1 = C(4);
cout << obj1.getX() << endl;
}
It looks like it does the assignment correctly, then calls the destructor on obj1 leaving x with a garbage value rather than a value of 4. If this is valid, why does it do this?
If there is a class C that has a constructor that takes an int, is this code valid?
C obj1(3); obj1=C(4);
Assuming C has an operator=(C) (which it will by default), the code is valid. What will happen is that in the first line obj1 is constructed with 3 as a the parameter to the constructor. Then on the second line, a temporary C object is constructed with 4 as a parameter and then operator= is invoked on obj1 with that temporary object as a parameter. After that the temporary object will be destructed.
If obj1 is in an invalid state after the assignment (but not before), there likely is a problem with C's operator=.
Update: If x really needs to be a pointer you have three options:
operator= so that it will create a copy of the integer instead of a copy of the value. If in your real code you use a pointer to something that's much bigger than an int, this might be too expensive.If C contains a pointer to something, you pretty much always need to implement operator=. In your case it would have this signature
class C
{
public:
void operator=(const C& rhs)
{
// For each member in rhs, copy it to ourselves
}
// Your other member variables and methods go here...
};
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