Code:
printfn "%10s" "abc"
printfn "%-10s" "abc"
printfn "%10d" 123
printfn "%-10d" 123
printfn "%10c" 'a'
printfn "%-10c" 'a'
Output:
abc
abc
123
123
a
a
So right aligning %c
does not work as I expect...
F# 2.0 build 4.0.30319.1
I don't think that the fact that it is missing in the table of valid types is causing the issue (the "%c" modifier is definitely supported, because the type of printfn "%c"
is char -> unit
as you would expect). So, it does look like a bug to me.
An easy workaround is to use the "%O" modifier which takes any type (also including char
values) and formats it using ToString
method (avaliable for all .NET types):
> printfn "%10O" 'a';;
a
val it : unit
BTW: I looked at the F# library source code (from the CTP release) and here is the relevant bit from printf.fs
(line 478):
| 's',nobj::args ->
formatString outputChar info width (unbox nobj) false; i+1,args
| 'c',nobj::args ->
outputChar (unbox nobj); i+1,args // (1)
| 'b',nobj::args ->
formatString outputChar info width
(if (unbox nobj) then "true" else "false") false; i+1,args
| 'O',xobj::args ->
formatString outputChar info width
(match xobj with null -> "<null>" | _ -> xobj.ToString()) false; i+1,args
The line (1) formats a character and it ignores the width
parameter (which is the width you specified). So, unless this is (for some reason, e.g. performance?) intended behavior, it really feels looks a bug!
I suppose that the following implementation would fix the problem (Brian ;-)! Are you there?):
| 'c', nobj::args ->
formatString outputChar info width
(string ((unbox nobj):char)) false; i+1,args
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