I need a SQL statement to retrieve records where it key (or any column) is in a associate table, for example:
documentId termId
4 1
4 2
3 3
5 1
This:
SELECT documentId
FROM table
WHERE termId IN (1,2,3)
...will retrieve any documentid
value where the termid
value is 1 or 2 or 3.
Is there something like this but return documentid
values where the termid
values are 1 and 2 and 3? Like an IN but with AND.
The MySQL LIKE OperatorThe LIKE operator is used in a WHERE clause to search for a specified pattern in a column. There are two wildcards often used in conjunction with the LIKE operator: The percent sign (%) represents zero, one, or multiple characters.
There is no combination of LIKE & IN in SQL, much less in TSQL (SQL Server) or PLSQL (Oracle). Part of the reason for that is because Full Text Search (FTS) is the recommended alternative.
The symbol <> in MySQL is same as not equal to operator (!=). Both gives the result in boolean or tinyint(1). If the condition becomes true, then the result will be 1 otherwise 0. Case 1 − Using !=
= in SQL does exact matching. LIKE does wildcard matching, using '%' as the multi-character match symbol and '_' as the single-character match symbol. '\' is the default escape character. foobar = '$foo' and foobar LIKE '$foo' will behave the same, because neither string contains a wildcard.
There's no straight forward functionality, but there are two options:
SELECT t.documentid
FROM TABLE t
WHERE t.termid IN (1,2,3)
GROUP BY t.documentid
HAVING COUNT(DISINCT t.termid) = 3
The caveat is that you have to use HAVING COUNT(DISTINCT
because duplicates of termid being 2 for the same documentid would be a false positive. And the COUNT has to equal the number of termid values in the IN clause.
SELECT t.documentid
FROM TABLE t
JOIN TABLE x ON x.termid = t.termid
AND x.termid = 1
JOIN TABLE y ON y.termid = t.termid
AND y.termid = 2
JOIN TABLE z ON z.termid = t.termid
AND z.termid = 3
But this one can be a pain for handling criteria that changes a lot.
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