I am trying to invoke a method that returns void (Java primitive type). I would like to delay the invoking of a it by a predefined amount of milliseconds. I know this can be simply done using a Handler
by I prefer not to use it.
I tried to do:
Observable.just(getView().setAttachments(attachments)).delay(50, TimeUnit.MILLISECONDS);
However, there is a compilation error, that:
Observable.just(java.lang.Void) cannot be applied to (void)
Is there another way? The reason I would like not to use a Handler
is that the code is defined in Presenter (MVP pattern) and I would not like to use Android specific code in Java only class.
I would prefer it to be a cold Observable, as I would not have to subscribe to it, just invoke the method only once.
You can achieve this with defer, delay and doOnNext.
Observable.defer(() -> Observable.just(null)
.delay(3, TimeUnit.SECONDS))
.doOnNext(ignore -> LogUtils.d("You action goes here"))
.subscribe();
In RxJava 2 you can use the following:
Completable.complete()
.delay(3, TimeUnit.SECONDS)
.doOnComplete(() -> System.out.println("Time to complete " + (System.currentTimeMillis() - start)))
.subscribe();
Test code for Paul's version:
@Test
public void testTimeToDoOnSubscribeExecution() {
final long startTime = System.currentTimeMillis();
System.out.println("Starting at: " + startTime);
Subscription subscription = Observable.empty()
.doOnSubscribe(() -> System.out.println("Time to invoke onSubscribe: " + (System.currentTimeMillis() - startTime)))
.delay(1000, TimeUnit.MILLISECONDS)
.subscribe();
new TestSubscriber((rx.Observer) subscription).awaitTerminalEvent(2, TimeUnit.SECONDS);
}
Output:
Starting at: 1467280697232
Time to invoke onSubscribe: 122
Use simply
subscription = Observable.timer(1000, TimeUnit.MILLISECONDS)
.subscribeOn(Schedulers.io())
.observeOn(AndroidSchedulers.mainThread())
.subscribe(aLong -> whatToDo());
private void whatToDo() {
System.out.println("Called after 1 second");
}
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