Is there any difference between flatten and flatMap(identity)?

Question

scala> List(List(1), List(2), List(3), List(4))
res18: List[List[Int]] = List(List(1), List(2), List(3), List(4))

scala> res18.flatten
res19: List[Int] = List(1, 2, 3, 4)

scala> res18.flatMap(identity)
res20: List[Int] = List(1, 2, 3, 4)

Is there any difference between these two functions? When is it appropriate to use one over the other? Are there any tradeoffs?

Answer 1

You can view flatMap(identity) as map(identity).flatten. (Of course it is not implemented that way, since it would take two iterations).

map(identity) gives you the same collection, so in the end it is the same as only flatten.

I would personally stick to flatten, since it is shorter/easier to understand and designed to exactly do this.

Answer 2

Conceptually there is no difference in the result... flatMap is taking bit more time to produce same result...

I will show it more practically with an example of flatMap, map & then flatten and flatten

object Test extends App {
  // flatmap
  println(timeElapsed(List(List(1, 2, 3, 4), List(5, 6, 7, 8)).flatMap(identity)))
  // map and then flatten
  println(timeElapsed(List(List(1, 2, 3, 4), List(5, 6, 7, 8)).map(identity).flatten))
  // flatten
  println(timeElapsed(List(List(1, 2, 3, 4), List(5, 6, 7, 8)).flatten))

  /**
   * timeElapsed
   */
  def timeElapsed[T](block: => T): T = {
    val start = System.nanoTime()
    val res = block
    val totalTime = System.nanoTime - start
    println("Elapsed time: %1d nano seconds".format(totalTime))
    res
  }
}

---

Both flatMap and flatten executed with same result after repeating several times

Conclusion : flatten is efficient

Elapsed time: 2915949 nano seconds
List(1, 2, 3, 4, 5, 6, 7, 8)
Elapsed time: 1060826 nano seconds
List(1, 2, 3, 4, 5, 6, 7, 8)
Elapsed time: 81172 nano seconds
List(1, 2, 3, 4, 5, 6, 7, 8)