Is there an easy way in .NET to get "st", "nd", "rd" and "th" endings for numbers? [duplicate]

Question

I am wondering if there is a method or format string I'm missing in .NET to convert the following:

   1 to 1st    2 to 2nd    3 to 3rd    4 to 4th   11 to 11th  101 to 101st  111 to 111th 

This link has a bad example of the basic principle involved in writing your own function, but I am more curious if there is an inbuilt capacity I'm missing.

Solution

Scott Hanselman's answer is the accepted one because it answers the question directly.

For a solution however, see this great answer.

Answer 1

It's a function which is a lot simpler than you think. Though there might be a .NET function already in existence for this, the following function (written in PHP) does the job. It shouldn't be too hard to port it over.

function ordinal($num) {     $ones = $num % 10;     $tens = floor($num / 10) % 10;     if ($tens == 1) {         $suff = "th";     } else {         switch ($ones) {             case 1 : $suff = "st"; break;             case 2 : $suff = "nd"; break;             case 3 : $suff = "rd"; break;             default : $suff = "th";         }     }     return $num . $suff; } 

Answer 2

Simple, clean, quick

    private static string GetOrdinalSuffix(int num)     {         string number = num.ToString();         if (number.EndsWith("11")) return "th";         if (number.EndsWith("12")) return "th";         if (number.EndsWith("13")) return "th";         if (number.EndsWith("1")) return "st";         if (number.EndsWith("2")) return "nd";         if (number.EndsWith("3")) return "rd";         return "th";     } 

Or better yet, as an extension method

public static class IntegerExtensions {     public static string DisplayWithSuffix(this int num)     {         string number = num.ToString();         if (number.EndsWith("11")) return number + "th";         if (number.EndsWith("12")) return number + "th";         if (number.EndsWith("13")) return number + "th";         if (number.EndsWith("1")) return number + "st";         if (number.EndsWith("2")) return number + "nd";         if (number.EndsWith("3")) return number + "rd";         return number + "th";     } } 

Now you can just call

int a = 1; a.DisplayWithSuffix();  

or even as direct as

1.DisplayWithSuffix();