Is there a way to synchronously run a C# task and get the result in one line of code?

Question

I have an async method which works when I call it as follows:

var result = await someClass.myAsyncMethod(someParameter);

Is it possible to do something like this, but in one line of code?

var task = someClass.myAsyncMethod(someParameter);
task.RunSynchronously();
var result = task.Result;

Answer 1

Yes you can do it using the Result property directly after the calling of method:

var result = someClass.myAsyncMethod(someParameter).Result;

and a more better way is to wrap it in Task.Run() to avoid deadlocks like:

var result = Task.Run(() => {

   return someClass.myAsyncMethod(someParameter);

}).Result;

I also found this RunSynchronously() method on MSDN, but that won't server your question as you want a on liner simple code.

Answer 2

If you find yourself doing this often you can write a small extension

public static class TaskExtensions
{
    public static T SyncResult<T>(this Task<T> task)
    {
        task.RunSynchronously();
        return task.Result;
    }
}

Then you can use:

var result = Task.SyncResult();