Is there a way to get function name inside a C++ function?

Question

I want to implement a function tracer, which would trace how much time a function is taking to execute. I have following class for the same:-

class FuncTracer {     public:         FuncTracer(LPCTSTR strFuncName_in)         {             m_strFuncName[0] = _T('\0');             if( strFuncName_in ||                 _T('\0') != strFuncName_in[0])             {                    _tcscpy(m_strFuncName,strFuncName_in);                  TCHAR strLog[MAX_PATH];                 _stprintf(strLog,_T("Entering Func:- <%s>"),m_strFuncName);                 LOG(strLog)                  m_dwEnterTime = GetTickCount();             }         }          ~FuncTracer()         {             TCHAR strLog[MAX_PATH];             _stprintf(strLog,_T("Leaving Func:- <%s>, Time inside the func <%d> ms"),m_strFuncName, GetTickCount()-m_dwEnterTime);             LOG(strLog)         }      private:         TCHAR m_strFuncName[MAX_PATH];         DWORD m_dwEnterTime; };  void TestClass::TestFunction() {     // I want to avoid writing the function name maually..     // Is there any macro (__LINE__)or some other way to      // get the function name inside a function ??      FuncTracer(_T("TestClass::TestFunction"));     /*      * Rest of the function code.      */ } 

I want to know if there is any way to get the name of the function from inside of a function? Basically I want the users of my class to simply create an object the same. They may not pass the function name.

Answer 1

C99 has __func__, but for C++ this will be compiler specific. On the plus side, some of the compiler-specific versions provide additional type information, which is particularly nice when you're tracing inside a templatized function/class.

• MSVC: __FUNCTION__, __FUNCDNAME__, __FUNCSIG__
• GCC: __func__, __FUNCTION__, __PRETTY_FUNCTION__

Boost library has defined macro BOOST_CURRENT_FUNCTION for most C++ compilers in header boost/current_function.hpp. If the compiler is too old to support this, the result will be "(unknown)".