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Is there a std::less/std::greater for the spaceship operator?

All the basic comparisons (<, <=, ==, !=, >=, >) have an associated function object (std::less, std::less_equal, std::equal_to, std::not_equal_to, std::greater_equal, std::greater).

Does the spaceship operator <=> have a similar function object? If not, why was it not added to the standard library?

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rubenvb Avatar asked Sep 21 '20 11:09

rubenvb


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How do you define a spaceship operator in C++?

The three-way comparison operator “<=>” is called a spaceship operator. The spaceship operator determines for two objects A and B whether A < B, A = B, or A > B. The spaceship operator or the compiler can auto-generate it for us.

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Spaceship Operator is used to compare two expressions. It returns -1, 0 or 1 when first expression is respectively less than, equal to, or greater than second expression.

What is std :: less?

The std::less is a is a member of the functional class (<functional. h>) used for performing comparisons.

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Some very smart people on the standardization committee noticed that the spaceship operator will always perform a lexicographic comparison of elements no matter what. Unconditionally performing lexicographic comparisons can lead to inefficient generated code with the equality operator in particular. The canonical example is comparing two strings.

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The spaceship operator is a welcomed addition to C++ and it is one of the features that will simplify and help you to write less code, and, sometimes, less is more. So buckle up with C++20’s spaceship operator!

How has the addition of the spaceship operator changed comaprison semantics?

The new addition of the spaceship operator has considerably changed how the comparison is viewed. It has affected how comaprison semantics work at the language level.

Is the spaceship operator available in Visual Studio 2019?

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1 Answers

std::compare_three_way is the function object for three-way comparison (aka. spaceship operator).

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Yksisarvinen Avatar answered Oct 12 '22 01:10

Yksisarvinen