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My problem is that i want to check the browserstring with pure regex.
Mozilla/5.0 (Linux; U; Android 3.0; en-us; Xoom Build/HRI39) AppleWebKit/534.13 (KHTML, like Gecko) Version/4.0 Safari/534.13 -> should match
Mozilla/5.0 (Linux; U; Android 2.2.1; en-us; Nexus One Build/FRG83) AppleWebKit/533.1 (KHTML, like Gecko) Version/4.0 Mobile Safari/533.1 should not match
my tried solution is: /?((?<=Android)(?:[^])*?(?=Mobile))/i but it matches exactly wrong.
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In order to match a line that does not contain something, use negative lookahead (described in Recipe 2.16). Notice that in this regular expression, a negative lookahead and a dot are repeated together using a noncapturing group.
$ means "Match the end of the string" (the position after the last character in the string). Both are called anchors and ensure that the entire string is matched instead of just a substring.
[] denotes a character class. () denotes a capturing group. [a-z0-9] -- One character that is in the range of a-z OR 0-9. (a-z0-9) -- Explicit capture of a-z0-9 .
You use look ahead assertions to check if a string contains a word or not.
If you want to assure that the string contains "Android" at some place you can do it like this:
^(?=.*Android).* You can also combine them, to ensure that it contains "Android" at some place AND "Mobile" at some place:
^(?=.*Android)(?=.*Mobile).* If you want to ensure that a certain word is NOT in the string, use the negative look ahead:
^(?=.*Android)(?!.*Mobile).* This would require the word "Android to be in the string and the word "Mobile" is not allowed in the string. The .* part matches then the complete string/row when the assertions at the beginning are true.
See it here on Regexr
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