Is there a Python equivalent of Ruby's 'any?' function?

Question

In Ruby, you can call Enumerable#any? on a enumerable object to see if any of its elements satisfies the predicate you pass in the block. Like so:

lst.any?{|e| pred(e) }

In Python, there's an any function that does something similar, but on a list of booleans.

Of course, for a reasonably-sized list, I'd just do:

any(map(pred,lst))

However, if my list is very long, I don't want to have to do the entire map operation first.

So, the question: Is there a generic short-circuiting any function in Python?

Yes, I know it's really trivial to write one myself, but I'd like to use speedy builtin functions (and also not reinvent any wheels).

Answer 1

any(pred(x) for x in lst)

alternatively

from itertools import imap
any(imap(pred, lst))