I was wondering if there is a "&" logical operator in Javascript. I tried running 1 & 0 and 1 && 0 in Firebug(Firefox) and it returned a 0 for both.
Someone told me that C# accepts both & and double &&, double being more efficient as it will exit the comparison loop as soon as a false is encountered, but I was not able to find any info for Javascript on that.
Any ideas?
No. &
is a bitwise AND operator. &&
is the only logical AND operator in Javascript.
The &&
operator returns 0
for the expression 1 && 0
because its semantics are different than those of the same operator (well, symbolically the same) in other C-like languages.
In Javascript, the &&
operator does coerce its operands to boolean values, but only for the purposes of evaluation. The result of an expression of the form
e1 && e2 && e3 ...
is the actual value of the first subexpression en
whose coerced boolean value is false
. If they're all true
when coerced to boolean, then the result is the actual value of the last en
. Similarly, the ||
operator interprets an expression like this:
e1 || e2 || e3 ...
by returning the actual value of the first en
whose coerced boolean value is true
. If they're all false, then the value is the actual value of the last one.
Implicit in those descriptions is the fact that both &&
and ||
stop evaluating the subexpressions as soon as their conditions for completion are met.
1 & 0 is 0.
It's a bitwise operator, not a logical operator.
&& means a logical AND of the left and right operators. This means it will return a boolean true value only if both the left and right operators resolve to boolean true.
& means a bitwise AND of the left and right operators. This means the bits of each operand will be compared and the result will be the ANDed value, not a boolean. If you do 101 & 100
the return value is 100
. If you do 1 & 0
, the return value is 0
.
You've been mislead about the meaning of the two operators if someone told you the difference was just in efficiency. They have very different uses.
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