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Is there a java implementation of Porter2 stemmer

Do you know any java implementation of the Porter2 stemmer(or any better stemmer written in java)? I know that there is a java version of Porter(not Porter2) here :

http://tartarus.org/~martin/PorterStemmer/java.txt

but on http://tartarus.org/~martin/PorterStemmer/ the author mentions that the Porter is bit outdated and recommends to use Porter2, available at

http://snowball.tartarus.org/algorithms/english/stemmer.html

However, the problem with me is that this Porter2 is written in snowball(I never heard of it before, so don't know anything about it). What I am exactly looking for is a java version of it.

Thanks. Your help will he highly appreciated.

like image 509
Bikash Gyawali Avatar asked Dec 09 '10 10:12

Bikash Gyawali


People also ask

What is the difference between Porter Stemmer and snowball Stemmer?

Difference Between Porter Stemmer and Snowball Stemmer: There is only a little difference in the working of these two. Words like 'fairly' and 'sportingly' were stemmed to 'fair' and 'sport' in the snowball stemmer but when you use the porter stemmer they are stemmed to 'fairli' and 'sportingli'.

Where is Porter Stemmer used?

The main applications of Porter Stemmer include data mining and Information retrieval. However, its applications are only limited to English words. Also, the group of stems is mapped on to the same stem and the output stem is not necessarily a meaningful word.

What does Lancaster Stemmer do?

Lancaster Stemmer – LancasterStemmer() Over-stemming renders stems non-linguistic or meaningless. LancasterStemmer() is a module in NLTK that implements the Lancaster stemming technique.

What is Porter Stemmer algorithm in NLP?

The Porter stemming algorithm (or 'Porter stemmer') is a process for removing the commoner morphological and inflexional endings from words in English. Its main use is as part of a term normalisation process that is usually done when setting up Information Retrieval systems.


2 Answers

The Snowball algo is available as a Java download

And from snowball.tartarus.org:

Feb 2002 - Java support Richard has modified the snowball code generator to produce Java output as well as ANSI C output. This means that pure Java systems can now use the snowball stemmers.

This is what you want, right?

You can create an instance of it like so:

  Class stemClass = Class.forName("org.tartarus.snowball.ext." + lang + "Stemmer");
  stemmer = (SnowballProgram) stemClass.newInstance();
  stemmer.setCurrent("your_word");
  stemmer.stem();
  String your_stemmed_word = stemmer.getCurrent();  
like image 139
Joel Avatar answered Nov 15 '22 10:11

Joel


/*

   Porter stemmer in Java. The original paper is in

       Porter, 1980, An algorithm for suffix stripping, Program, Vol. 14,
       no. 3, pp 130-137,

   See also http://www.tartarus.org/~martin/PorterStemmer

   History:

   Release 1

   Bug 1 (reported by Gonzalo Parra 16/10/99) fixed as marked below.
   The words 'aed', 'eed', 'oed' leave k at 'a' for step 3, and b[k-1]
   is then out outside the bounds of b.

   Release 2

   Similarly,

   Bug 2 (reported by Steve Dyrdahl 22/2/00) fixed as marked below.
   'ion' by itself leaves j = -1 in the test for 'ion' in step 5, and
   b[j] is then outside the bounds of b.

   Release 3

   Considerably revised 4/9/00 in the light of many helpful suggestions
   from Brian Goetz of Quiotix Corporation ([email protected]).

   Release 4

*/

import java.io.*;

/**
  * Stemmer, implementing the Porter Stemming Algorithm
  *
  * The Stemmer class transforms a word into its root form.  The input
  * word can be provided a character at time (by calling add()), or at once
  * by calling one of the various stem(something) methods.
  */

class Stemmer
{  private char[] b;
   private int i,     /* offset into b */
               i_end, /* offset to end of stemmed word */
               j, k;
   private static final int INC = 50;
                     /* unit of size whereby b is increased */
   public Stemmer()
   {  b = new char[INC];
      i = 0;
      i_end = 0;
   }

   /**
    * Add a character to the word being stemmed.  When you are finished
    * adding characters, you can call stem(void) to stem the word.
    */

   public void add(char ch)
   {  if (i == b.length)
      {  char[] new_b = new char[i+INC];
         for (int c = 0; c < i; c++) new_b[c] = b[c];
         b = new_b;
      }
      b[i++] = ch;
   }


   /** Adds wLen characters to the word being stemmed contained in a portion
    * of a char[] array. This is like repeated calls of add(char ch), but
    * faster.
    */

   public void add(char[] w, int wLen)
   {  if (i+wLen >= b.length)
      {  char[] new_b = new char[i+wLen+INC];
         for (int c = 0; c < i; c++) new_b[c] = b[c];
         b = new_b;
      }
      for (int c = 0; c < wLen; c++) b[i++] = w[c];
   }

   /**
    * After a word has been stemmed, it can be retrieved by toString(),
    * or a reference to the internal buffer can be retrieved by getResultBuffer
    * and getResultLength (which is generally more efficient.)
    */
   public String toString() { return new String(b,0,i_end); }

   /**
    * Returns the length of the word resulting from the stemming process.
    */
   public int getResultLength() { return i_end; }

   /**
    * Returns a reference to a character buffer containing the results of
    * the stemming process.  You also need to consult getResultLength()
    * to determine the length of the result.
    */
   public char[] getResultBuffer() { return b; }

   /* cons(i) is true <=> b[i] is a consonant. */

   private final boolean cons(int i)
   {  switch (b[i])
      {  case 'a': case 'e': case 'i': case 'o': case 'u': return false;
         case 'y': return (i==0) ? true : !cons(i-1);
         default: return true;
      }
   }

   /* m() measures the number of consonant sequences between 0 and j. if c is
      a consonant sequence and v a vowel sequence, and <..> indicates arbitrary
      presence,

         <c><v>       gives 0
         <c>vc<v>     gives 1
         <c>vcvc<v>   gives 2
         <c>vcvcvc<v> gives 3
         ....
   */

   private final int m()
   {  int n = 0;
      int i = 0;
      while(true)
      {  if (i > j) return n;
         if (! cons(i)) break; i++;
      }
      i++;
      while(true)
      {  while(true)
         {  if (i > j) return n;
               if (cons(i)) break;
               i++;
         }
         i++;
         n++;
         while(true)
         {  if (i > j) return n;
            if (! cons(i)) break;
            i++;
         }
         i++;
       }
   }

   /* vowelinstem() is true <=> 0,...j contains a vowel */

   private final boolean vowelinstem()
   {  int i; for (i = 0; i <= j; i++) if (! cons(i)) return true;
      return false;
   }

   /* doublec(j) is true <=> j,(j-1) contain a double consonant. */

   private final boolean doublec(int j)
   {  if (j < 1) return false;
      if (b[j] != b[j-1]) return false;
      return cons(j);
   }

   /* cvc(i) is true <=> i-2,i-1,i has the form consonant - vowel - consonant
      and also if the second c is not w,x or y. this is used when trying to
      restore an e at the end of a short word. e.g.

         cav(e), lov(e), hop(e), crim(e), but
         snow, box, tray.

   */

   private final boolean cvc(int i)
   {  if (i < 2 || !cons(i) || cons(i-1) || !cons(i-2)) return false;
      {  int ch = b[i];
         if (ch == 'w' || ch == 'x' || ch == 'y') return false;
      }
      return true;
   }

   private final boolean ends(String s)
   {  int l = s.length();
      int o = k-l+1;
      if (o < 0) return false;
      for (int i = 0; i < l; i++) if (b[o+i] != s.charAt(i)) return false;
      j = k-l;
      return true;
   }

   /* setto(s) sets (j+1),...k to the characters in the string s, readjusting
      k. */

   private final void setto(String s)
   {  int l = s.length();
      int o = j+1;
      for (int i = 0; i < l; i++) b[o+i] = s.charAt(i);
      k = j+l;
   }

   /* r(s) is used further down. */

   private final void r(String s) { if (m() > 0) setto(s); }

   /* step1() gets rid of plurals and -ed or -ing. e.g.

          caresses  ->  caress
          ponies    ->  poni
          ties      ->  ti
          caress    ->  caress
          cats      ->  cat

          feed      ->  feed
          agreed    ->  agree
          disabled  ->  disable

          matting   ->  mat
          mating    ->  mate
          meeting   ->  meet
          milling   ->  mill
          messing   ->  mess

          meetings  ->  meet

   */

   private final void step1()
   {  if (b[k] == 's')
      {  if (ends("sses")) k -= 2; else
         if (ends("ies")) setto("i"); else
         if (b[k-1] != 's') k--;
      }
      if (ends("eed")) { if (m() > 0) k--; } else
      if ((ends("ed") || ends("ing")) && vowelinstem())
      {  k = j;
         if (ends("at")) setto("ate"); else
         if (ends("bl")) setto("ble"); else
         if (ends("iz")) setto("ize"); else
         if (doublec(k))
         {  k--;
            {  int ch = b[k];
               if (ch == 'l' || ch == 's' || ch == 'z') k++;
            }
         }
         else if (m() == 1 && cvc(k)) setto("e");
     }
   }

   /* step2() turns terminal y to i when there is another vowel in the stem. */

   private final void step2() { if (ends("y") && vowelinstem()) b[k] = 'i'; }

   /* step3() maps double suffices to single ones. so -ization ( = -ize plus
      -ation) maps to -ize etc. note that the string before the suffix must give
      m() > 0. */

   private final void step3() { if (k == 0) return; /* For Bug 1 */ switch (b[k-1])
   {
       case 'a': if (ends("ational")) { r("ate"); break; }
                 if (ends("tional")) { r("tion"); break; }
                 break;
       case 'c': if (ends("enci")) { r("ence"); break; }
                 if (ends("anci")) { r("ance"); break; }
                 break;
       case 'e': if (ends("izer")) { r("ize"); break; }
                 break;
       case 'l': if (ends("bli")) { r("ble"); break; }
                 if (ends("alli")) { r("al"); break; }
                 if (ends("entli")) { r("ent"); break; }
                 if (ends("eli")) { r("e"); break; }
                 if (ends("ousli")) { r("ous"); break; }
                 break;
       case 'o': if (ends("ization")) { r("ize"); break; }
                 if (ends("ation")) { r("ate"); break; }
                 if (ends("ator")) { r("ate"); break; }
                 break;
       case 's': if (ends("alism")) { r("al"); break; }
                 if (ends("iveness")) { r("ive"); break; }
                 if (ends("fulness")) { r("ful"); break; }
                 if (ends("ousness")) { r("ous"); break; }
                 break;
       case 't': if (ends("aliti")) { r("al"); break; }
                 if (ends("iviti")) { r("ive"); break; }
                 if (ends("biliti")) { r("ble"); break; }
                 break;
       case 'g': if (ends("logi")) { r("log"); break; }
   } }

   /* step4() deals with -ic-, -full, -ness etc. similar strategy to step3. */

   private final void step4() { switch (b[k])
   {
       case 'e': if (ends("icate")) { r("ic"); break; }
                 if (ends("ative")) { r(""); break; }
                 if (ends("alize")) { r("al"); break; }
                 break;
       case 'i': if (ends("iciti")) { r("ic"); break; }
                 break;
       case 'l': if (ends("ical")) { r("ic"); break; }
                 if (ends("ful")) { r(""); break; }
                 break;
       case 's': if (ends("ness")) { r(""); break; }
                 break;
   } }

   /* step5() takes off -ant, -ence etc., in context <c>vcvc<v>. */

   private final void step5()
   {   if (k == 0) return; /* for Bug 1 */ switch (b[k-1])
       {  case 'a': if (ends("al")) break; return;
          case 'c': if (ends("ance")) break;
                    if (ends("ence")) break; return;
          case 'e': if (ends("er")) break; return;
          case 'i': if (ends("ic")) break; return;
          case 'l': if (ends("able")) break;
                    if (ends("ible")) break; return;
          case 'n': if (ends("ant")) break;
                    if (ends("ement")) break;
                    if (ends("ment")) break;
                    /* element etc. not stripped before the m */
                    if (ends("ent")) break; return;
          case 'o': if (ends("ion") && j >= 0 && (b[j] == 's' || b[j] == 't')) break;
                                    /* j >= 0 fixes Bug 2 */
                    if (ends("ou")) break; return;
                    /* takes care of -ous */
          case 's': if (ends("ism")) break; return;
          case 't': if (ends("ate")) break;
                    if (ends("iti")) break; return;
          case 'u': if (ends("ous")) break; return;
          case 'v': if (ends("ive")) break; return;
          case 'z': if (ends("ize")) break; return;
          default: return;
       }
       if (m() > 1) k = j;
   }

   /* step6() removes a final -e if m() > 1. */

   private final void step6()
   {  j = k;
      if (b[k] == 'e')
      {  int a = m();
         if (a > 1 || a == 1 && !cvc(k-1)) k--;
      }
      if (b[k] == 'l' && doublec(k) && m() > 1) k--;
   }

   /** Stem the word placed into the Stemmer buffer through calls to add().
    * Returns true if the stemming process resulted in a word different
    * from the input.  You can retrieve the result with
    * getResultLength()/getResultBuffer() or toString().
    */
   public void stem()
   {  k = i - 1;
      if (k > 1) { step1(); step2(); step3(); step4(); step5(); step6(); }
      i_end = k+1; i = 0;
   }

   /** Test program for demonstrating the Stemmer.  It reads text from a
    * a list of files, stems each word, and writes the result to standard
    * output. Note that the word stemmed is expected to be in lower case:
    * forcing lower case must be done outside the Stemmer class.
    * Usage: Stemmer file-name file-name ...
    */
   public static void main(String[] args)
   {
      char[] w = new char[501];
      Stemmer s = new Stemmer();
      for (int i = 0; i < args.length; i++)
      try
      {
         FileInputStream in = new FileInputStream(args[i]);

         try
         { while(true)

           {  int ch = in.read();
              if (Character.isLetter((char) ch))
              {
                 int j = 0;
                 while(true)
                 {  ch = Character.toLowerCase((char) ch);
                    w[j] = (char) ch;
                    if (j < 500) j++;
                    ch = in.read();
                    if (!Character.isLetter((char) ch))
                    {
                       /* to test add(char ch) */
                       for (int c = 0; c < j; c++) s.add(w[c]);

                       /* or, to test add(char[] w, int j) */
                       /* s.add(w, j); */

                       s.stem();
                       {  String u;

                          /* and now, to test toString() : */
                          u = s.toString();

                          /* to test getResultBuffer(), getResultLength() : */
                          /* u = new String(s.getResultBuffer(), 0, s.getResultLength()); */

                          System.out.print(u);
                       }
                       break;
                    }
                 }
              }
              if (ch < 0) break;
              System.out.print((char)ch);
           }
         }
         catch (IOException e)
         {  System.out.println("error reading " + args[i]);
            break;
         }
      }
      catch (FileNotFoundException e)
      {  System.out.println("file " + args[i] + " not found");
         break;
      }
   }
}
like image 37
Raja Avatar answered Nov 15 '22 08:11

Raja