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Is there a IPython notebook api?

Tags:

python

ipython

I would like to generate several notebooks from a python script. Is there an API to write IPython notebooks?

like image 209
alex Avatar asked Oct 03 '22 09:10

alex


1 Answers

There is, you can do:

import io
from IPython.nbformat import current

def convert(py_file, ipynb_file):
    with io.open(py_file, 'r', encoding='utf-8') as f:
        notebook = current.reads(f.read(), format='py')
    with io.open(ipynb_file, 'w', encoding='utf-8') as f:
        current.write(notebook, f, format='ipynb')

convert('test.py', 'test.ipynb')

But it's not that smart and it will place all the code from the python file into one IPython Notebook cell. But you can always do a little bit of parsing.

import io
import re
from IPython.nbformat import current

def parse_into_cells(py_file):
    with io.open(py_file, 'r', encoding='utf-8') as f:
        data = f.readlines()
    in_cell = True
    cell = ''
    for line in data:
        if line.rstrip() == '':
            # If a blank line occurs I'm out of the current cell
            in_cell = False
        elif re.match('^\s+', line):
            # Indentation, so nope, I'm not out of the current cell
            in_cell = True
            cell += line
        else:
            # Code at the beginning of the line, so if I'm in a cell just
            # append it, otherwise yield out the cell and start a new one
            if in_cell:
                cell += line
            else:
                yield cell.strip()
                cell = line
                in_cell = True
    if cell != '':
        yield cell.strip()

def convert(py_file, ipynb_file):
    # Create an empty notebook
    notebook = current.reads('', format='py')
    # Add all the parsed cells
    notebook['worksheets'][0]['cells'] = list(map(current.new_code_cell,
                                                  parse_into_cells(py_file)))
    # Save the notebook
    with io.open(ipynb_file, 'w', encoding='utf-8') as f:
        current.write(notebook, f, format='ipynb')

convert('convert.py', 'convert.ipynb')

Edit: Explaining the parsing

In the previous code a cell split is triggered whenever a blank line appears before a module level instruction (function, variable or class definition, import, etc.). That is whenever I see a line that is not indented and is preceded with a blank line). So:

import time
import datetime

Will be just one cell, but:

import time

import datetime

Will be two cells, and also

class Test(objet):

    def __init__(self, x):

        self.x = x

    def show(self):

        print(self.x)

class Foo(object):
     pass

will be two cells since there are only two top level definitions (lines that are not indented) that are preceded with a blank line (first line in the file is considered to be preceded with a blank line because it has to start a new cell).

like image 153
Viktor Kerkez Avatar answered Oct 12 '22 10:10

Viktor Kerkez