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Is there a function to make a copy of a PHP array to another?

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arrays

php

copy

Is there a function to make a copy of a PHP array to another?

I have been burned a few times trying to copy PHP arrays. I want to copy an array defined inside an object to a global outside it.

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vfclists Avatar asked Oct 07 '09 16:10

vfclists


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How do I copy one array to another in PHP?

The getArrayCopy() function of the ArrayObject class in PHP is used to create a copy of this ArrayObject. This function returns the copy of the array present in this ArrayObject.

How do I copy the contents of an array into another?

If you want to copy the first few elements of an array or a full copy of an array, you can use Arrays. copyOf() method. Arrays. copyOfRange() is used to copy a specified range of an array.


2 Answers

In PHP arrays are assigned by copy, while objects are assigned by reference. This means that:

$a = array(); $b = $a; $b['foo'] = 42; var_dump($a); 

Will yield:

array(0) { } 

Whereas:

$a = new StdClass(); $b = $a; $b->foo = 42; var_dump($a); 

Yields:

object(stdClass)#1 (1) {   ["foo"]=>   int(42) } 

You could get confused by intricacies such as ArrayObject, which is an object that acts exactly like an array. Being an object however, it has reference semantics.

Edit: @AndrewLarsson raises a point in the comments below. PHP has a special feature called "references". They are somewhat similar to pointers in languages like C/C++, but not quite the same. If your array contains references, then while the array itself is passed by copy, the references will still resolve to the original target. That's of course usually the desired behaviour, but I thought it was worth mentioning.

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troelskn Avatar answered Oct 05 '22 10:10

troelskn


PHP will copy the array by default. References in PHP have to be explicit.

$a = array(1,2); $b = $a; // $b will be a different array $c = &$a; // $c will be a reference to $a 
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slikts Avatar answered Oct 05 '22 08:10

slikts