Is there a compound assignment operator for a = b <operator> a (where <operator> is not commutative)?

Question

In a lot of languages a = a + b can be written as a += b In case of numerical operations, a + b is same as b + a, so the single compound operator suffices.

Also, a = a - b can be written as a -=b .

However, a-b is not equal to b-a. Hence, the compound assignment operator does not work for a = b - a

So, are there compound assignment operators for the operation a = b op a (where op can be +, -, *, /, %, and order matters) ?

[Non commutative operations]

Answer 1

No there isn't a short-hand notation for a = b + a. If you need to do a lot of a = b + a for strings, you'd better build a list like:

lst = []

...

lst.append("a")
lst.append("bb")
lst.append("ccc")
lst.append("dddd")

...

lst.reverse()

return ''.join(lst)   # "ddddcccbba"