Is there a cleaner way to iterate through all binary 4-tuples?

Question

This does what I want it to do:

import itertools
list(itertools.product(*[[0,1]]*4))

Output:

[(0, 0, 0, 0),
 (0, 0, 0, 1),
 (0, 0, 1, 0),
 (0, 0, 1, 1),
 (0, 1, 0, 0),
 (0, 1, 0, 1),
 (0, 1, 1, 0),
 (0, 1, 1, 1),
 (1, 0, 0, 0),
 (1, 0, 0, 1),
 (1, 0, 1, 0),
 (1, 0, 1, 1),
 (1, 1, 0, 0),
 (1, 1, 0, 1),
 (1, 1, 1, 0),
 (1, 1, 1, 1)]

But it's a bit obfuscated to me. Is there a more pythonic way to do it?

Answer 1

itertools.product takes a repeat argument which simplifies it a bit as it avoids the argument unpacking and therefor the list multiplication:

itertools.product(range(2), repeat=4)

This is even called out in the official documentation¹ (though the example uses repeat=3).

^{1Note, I used range(2) rather than (0, 1) or [0, 1] since that's how it's written in the documentation. Either way will work :) (obviously)}