I'm trying to run a query that checks if some conditions are true and returns a simple boolean result as output. What makes it slightly tricky is that one of the conditions is to test for whether no results are returned for a set of criteria.
I'm currently using JPA-2.0 with hibernate as my provider, backed by MySQL. I have gotten an example query working fine in MySQL, but when trying to get it running in JPQL it flops. The MySQL query looks a bit like this:
Select exists(Select statement with criteria)
or not exists(Select statement with criteria);
I also got the same output using CASE, but as JPQL doesn't support that statement.
Anyways, when I try to use a similar query in JPQL I get the error:
"unexpected end of subtree"
which from my understanding means that something is missing in the query. Does anyone have any idea how to fix it?
A subselect is a query embedded into another query. It's a powerful feature you probably know from SQL. Unfortunately, JPQL supports it only in the WHERE clause and not in the SELECT or FROM clause. Subqueries can return one or multiple records and can use the aliases defined in the outer query.
JPQL can retrieve information or data using SELECT clause, can do bulk updates using UPDATE clause and DELETE clause.
Query createQuery(String name) - The createQuery() method of EntityManager interface is used to create an instance of Query interface for executing JPQL statement.
We can also join multiple entities in a single JPQL query: @Test public void whenMultipleEntitiesAreListedWithJoin_ThenCreatesMultipleJoins() { TypedQuery<Phone> query = entityManager.
You can do a boolean query using a case expression.
As of JPA 2.0 (Java EE 6) you can create a TypedQuery .
String query = "select case when (count(*) > 0) then true else false end from ......"
TypedQuery<Boolean> booleanQuery = entityManager.createQuery(query, Boolean.class);
boolean exists = booleanQuery.getSingleResult();
In JPA 1.0 (Java EE 5) you must use an untyped query.
Query booleanQuery = entityManager.createQuery(query);
boolean exists = (Boolean) booleanQuery.getSingleResult();
This answer is obsolete. Please refer to correct answer from Rene Link
No, it is not possible.
Refer to the JPQL BNF documentation from oracle.
simple_cond_expression ::= comparison_expression | between_expression | like_expression | in_expression | null_comparison_expression | empty_collection_comparison_expression | collection_member_expression | exists_expression
exists_expression ::= [NOT] EXISTS(subquery)
In a project with Hibernate 5.2 (which supports JPA 2.1), and Spring Data Jpa 2.0.6, I successfully used this JPQL query:
@Query("SELECT COUNT(c) > 0 FROM Contract c WHERE c.person.id = :pid")
Boolean existContractForPerson(@Param("pid") Long personId);
In the logs, I read that the produced native query is the following:
select count(contract0_.contract_id)>0 as col_0_0_ from contracts contract0_ where contract0_.fk_person_id=?
Alternatively you could use a select count(...)
and test whether it returns 0
. This should be almost as efficient without requiring to write much more code (in fact, the query itself will probably look simpler).
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