Is Queue<T>.Enqueue(T) method thread-safe when it is used alone?

Question

Would it be thread-safe if I solely call Enqueue(T) from multiple threads simultaneously and wait for those threads to complete before calling Dequeue() or enumerating the queue?

var queue = new Queue<int>();
Action enqueue = () =>
{
    for (int i = 0; i < 100000; i++)
        queue.Enqueue(i);
};

var tasks = new[]
{
    new Task(enqueue),
    new Task(enqueue),
    new Task(enqueue)
};
foreach (var task in tasks)
    task.Start();

Task.Factory.ContinueWhenAll(tasks, t =>
{
    while (queue.Count > 0)
        Console.WriteLine(queue.Dequeue());
});

Answer 1

The documentation also states that instance members of this type are not thread safe (scroll down to the Thread Safety section).

The documentation also states:

A Queue can support multiple readers concurrently, as long as the collection is not modified.

However, this is just a by-product of the fact that concurrent reading does not mutate the list. It does not make the type "thread-safe". Thread-safety is best thought of as offering true support across all actions that define the public contract of the type (in this case, thread-safety in mutating the list also).

More tongue-in-cheek: the implementation of Enqueue doesn't include any thread synchronisation or locking primitives:

public void Enqueue(T item)
{
    if (this._size == this._array.Length)
    {
        int num = (int)((long)this._array.Length * 200L / 100L);
        if (num < this._array.Length + 4)
        {
            num = this._array.Length + 4;
        }
        this.SetCapacity(num);
    }
    this._array[this._tail] = item;
    this._tail = (this._tail + 1) % this._array.Length;
    this._size++;
    this._version++;
}

So I'm going with "no". There is ConcurrentQueue for multi-threaded support.