E.g.,
if (bool1 ^ bool2 ^ bool3 ^ bool4)
{
// Do whatever
}
It should execute only if exactly one of the conditions is met.
Add the bools together as integers and check if they equal 1.
In a language where casting from a boolean to an integer doesn't work, such as Java, the more long winded option is:
if ((bool1 ? 1 : 0) + (bool2 ? 1 : 0) + (bool3 ? 1 : 0) + (bool4 ? 1 : 0) == 1) {
// only runs when one of bool 1-4 is true
}
However, in other languages where casting a boolean to an integer is valid, you can do the following:
if ((int)(bool1) + (int)(bool2) + (int)(bool3) + (int)(bool4) == 1) {
// only runs when one of bool 1-4 is true
}
As an alternative, here is a stream-based solution:
boolean b0 = false;
boolean b1 = false;
boolean b2 = true;
boolean b3 = false;
boolean result = Stream.of(b0, b1, b2, b3)
.mapToInt(b -> b ? 1 : 0)
.sum() == 1;
System.out.println(result);
It has the advantage that it can easily be applied to 3 or 5 boolean values, or to generically implement a boolean exactlyOne(boolean ... b)
method.
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