Is it possible to spread the input array into arguments?

Question

So Promise.all passes an array as a value into the function, I would much rather it pass the array values as arguments.

Assume I have this function:

function printData(a,b,c){
   console.log(a,b,c)
}

I would like

Promise.all([1,2,3]).then(printData)
>> [1,2,3] undefined undefined

To print this instead

>> 1 2 3

Is there a better way of doing this:

Promise.all([1,2,3,4]).then(function(values){printData.apply(null, values)})

using the spread operator?

I also tried

Promise.all([1,2,3]).then(printData.apply)

But it returns an error

Answer 1

One way using ES 6 Destructuring

function printData(a,b,c){
   console.log(a,b,c)
}

Promise.all([1,2,3]).then( data => {var [a,b,c] = data;
                           printData(a,b,c);});

Using ES 6 Spread Syntax

function printData(a,b,c){
   console.log(a,b,c)
}

Promise.all([1,2,3]).then(data => printData(...data))