I am unit testing a class TestMe
using EasyMock, and one of its methods (say method(N n)
) expects a parameter of type N
which has a native method (say nativeMethod()
).
class TestMe {
void method(N n) {
// Do stuff
n.nativeMethod();
// Do more stuff
}
}
method()
needs to invoke N.nativeMethod()
at some point, and the problem I'm having is that my Easymock mock object for N is unable to override the native method. I do not own class N but I can refactor TestMe
in any way necessary.
I decided to make my own class FakeN extends N
which overrides nativeMethod
to do nothing:
class FakeN extends N {
FakeN(int pointer) {
super(pointer);
}
@Override
public void nativeMethod(Object o) {
// super.nativeMethod() is an actual native method defined as:
// public native void nativeMethod(Object o)
//
// IGNORE
}
}
but while the compiler does not complain, when I run the test it appears that N.nativeMethod()
is the one being invoked and not FakeN
s version.
Is there a workaround here that I can use?
The native
methods can be overridden just like any other methods, unless they are declared final
. Just be sure that you're calling TestMe.method(N n)
with an instance of FakeN
.
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