Like
<div id="box_1">
<div id="box_2">
<div id="box_3">
If i want to get all id's starting with 'box_' how can i do it something like this..
$("#box_" + anything )
Unfortunately wrapping the div's won't work because it will get all the other divs in side and between the box divs.
I guess i can give them all another class and reference it like that, but just wondering if there's something like this out there.. thanks.
You can use an Attribute Starts With selector:
$("div[id^=box_]");
It is possible with the attribute starts with selector as others have mentioned, but it might be better to give each element a class:
<div id="box_1" class="box"></div>
<div id="box_2" class="box"></div>
<div id="box_3" class="box"></div>
Select with:
$(".box")
Yep:
$('div[id^="box_"]');
In this case, because you are trying to use the ID selector, its better to switch to an element selector, combined with an attribute selector.
You can use an attribute selector:
$('[id^="box_"')
That will give you all elements whose id starts with "box_". If you need to, qualify it with an element:
$('div[id^="box_"')
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