Is it possible to execute the code in the try block again after an exception in caught in catch block?

Question

I want to execute the code in the try block again after an exception is caught. Is that possible somehow?

For Eg:

try {     //execute some code } catch(Exception e) { } 

If the exception is caught I want to go in the try block again to "execute some code" and try again to execute it.

Answer 1

Put it in a loop. Possibly a while loop around a boolean flag to control when you finally want to exit.

bool tryAgain = true; while(tryAgain){   try{     // execute some code;     // Maybe set tryAgain = false;   }catch(Exception e){     // Or maybe set tryAgain = false; here, depending upon the exception, or saved details from within the try.   } } 

Just be careful to avoid an infinite loop.

A better approach may be to put your "some code" within its own method, then you could call the method from both within the try and the catch as appropriate.

Answer 2

If you wrap your block in a method, you can recursively call it

void MyMethod(type arg1, type arg2, int retryNumber = 0) {     try     {         ...     }     catch(Exception e)     {         if (retryNumber < maxRetryNumber)             MyMethod(arg1, arg2, retryNumber+1)         else             throw;     } } 

or you could do it in a loop.

int retries = 0;  while(true) {     try     {         ...         break; // exit the loop if code completes     }     catch(Exception e)     {         if (retries < maxRetries)             retries++;         else             throw;     } }