Is it possible to create a gradient border on a CIRCLE with css3? [duplicate]

Question

I have an background image in shape of a circle. Have given it a yellow border. I would like to change the border to a gradient from yellow to white. I have seen many examples with square borders but none applied to circles. Here's my code:

.Profileimage{
  background-image: url("images/profilePic.jpg");
  background-repeat: no-repeat;
  background-size: cover;
  overflow:hidden;
  -webkit-border-radius:50px;
  -moz-border-radius:50px;
  border-radius:50%;
  width:100px;
  height:100px;
  border: 5px solid rgb(252,238,33); 
}

<div class="Profileimage"></div>

Thanks!!

Answer 1

This Is Your Answer:

#cont{
  background: -webkit-linear-gradient(left top, crimson 0%, #f90 100%);
  width: 300px;
  height: 300px;
  border-radius: 1000px;
  padding: 10px;
}

#box{
  background: black;
  width: 300px;
  height: 300px;
  border-radius: 1000px;
}

<div id="cont">
  <div id="box"></div>
</div>

Answer 2

Maybe something like this?

.Profileimage{
  position: relative;
  background: linear-gradient(rgb(252,238,33), rgb(255,255,255));
  -webkit-border-radius:50px;
  -moz-border-radius:50px;
  border-radius:50%;
  width:100px;
  height:100px;
}
.Profileimage:after{
  position: absolute;
  display: block;
  top: 5px;
  left: 5px;
  width: 90px;
  height: 90px;
  content: "";
  background-color: #fff;
  background-image: url("images/profilePic.jpg");
  background-repeat: no-repeat;
  background-size: cover;
  border-radius: 50%;
  overflow: hidden;
}

Not sure if that's what you're looking for, but you can just set the background to the gradient, and then position an element over the top (here I'm using the 'after' pseudo selector)

Fiddle: http://jsfiddle.net/6ue88pu6/1/