Is it possible to access outer local varialbe in a PHP sub-function?
In below code, I want to access variable $l in inner function bar. Declaring $l as global $l in bar doesn't work.
function foo() {     $l = "xyz";      function bar()     {         echo $l;     }     bar(); } foo(); 
                You could probably use a Closure, to do just that...
Edit : took some time to remember the syntax, but here's what it would look like :
function foo() {     $l = "xyz";     $bar = function () use ($l)     {         var_dump($l);     };     $bar(); } foo();   And, running the script, you'd get :
$ php temp.php string(3) "xyz"   
 A couple of note :
; after the function's declaration !use the variable by reference, with a & before it's name : use (& $l) For more informations, as a reference, you can take a look at this page in the manual : Anonymous functions
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