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If I have a simple function:
def add(a, b, c):
return a + b + c
Is it possible for me to make it so that if I supply an unused kwarg, it is simply ignored?
kwargs = dict(a=1, b=2, c=3, d=4)
print add(**kwargs) #prints 6
792
**kwargs allow a function to take any number of keyword arguments. By default, **kwargs is an empty dictionary. Each undefined keyword argument is stored as a key-value pair in the **kwargs dictionary.
*_ means multiple placeholders,just like you write def my_callbacK_handler(a, b, _,_,_....,_): and will create a variable named _ which is a list of the extra arguments. It has two advantage: It can handle the case where there is no extra argument.
Python 3.5+ allows passing multiple sets of keyword arguments ("kwargs") to a function within a single call, using the `"**"` syntax.
Kwargs allow you to pass keyword arguments to a function. They are used when you are not sure of the number of keyword arguments that will be passed in the function. Kwargs can be used for unpacking dictionary key, value pairs. This is done using the double asterisk notation ( ** ).
Sure. Just add **kwargs to the function signature:
def add(a, b, c, **kwargs):
return a + b + c
kwargs = dict(a=1, b=2, c=3, d=4)
print add(**kwargs)
#prints 6
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