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I always thought that in C, int stands for signed int ; but I have heard that this behavior is platform specific and in some platforms, int is unsigned by default. Is it true? What says the standard, and has it evolved over time?
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Yes, it is signed.
The range is the same, but it is shifted on the number line. An int type in C, C++, and C# is signed by default. If negative numbers are involved, the int must be signed; an unsigned int cannot represent a negative number.
The XDR standard defines signed integers as integer. A signed integer is a 32-bit datum that encodes an integer in the range [-2147483648 to 2147483647]. An unsigned integer is a 32-bit datum that encodes a nonnegative integer in the range [0 to 4294967295].
The int type in C is a signed integer, which means it can represent both negative and positive numbers. This is in contrast to an unsigned integer (which can be used by declaring a variable unsigned int), which can only represent positive numbers.
You are quite right. As per C11 (the latest c standard), chapter §6.7.2
int,signed, orsigned int
is categorized as same type (type specifiers, to be exact). So, int is the same as signed int.
Also, re-iterating the same, from chapter §6.2.5/P4
There are five standard signed integer types, designated as
signed char,short int,int,long int, andlong long int. (These and other types may be designated in several additional ways, as described in 6.7.2.) [....]
So, for any conforming environment, int stands for signed int and vice versa.
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