Is foreach
by-definition guaranteed to iterate the subject collection (if it defines order) sequentially from the very first to the very last (unless accidentally interrupted) element? Aren't there any compiler optimization switches which can brake it (shuffle the sequence) or plans to make the ordinary foreach
parallel in future versions?
The foreach function is applicable to both Scala's Mutable and Immutable collection data structures. The foreach method takes a function as parameter and applies it to every element in the collection. As an example, you can use foreach method to loop through all elements in a collection.
The foreach statement in some languages has some defined order, processing each item in the collection from the first to the last. The foreach statement in many other languages, especially array programming languages, does not have any particular order.
A simple for loop that iterates over a collection is translated to a foreach method call on the collection. A for loop with a guard (see Recipe 3.3) is translated to a sequence of a withFilter method call on the collection followed by a foreach call.
In scala, for loop is known as for-comprehensions. It can be used to iterate, filter and return an iterated collection.
Foreach is guaranteed to be sequential for sequential collections (that is, the normal hierarchy, or for anything transformed by .seq
). The parallel part of the collections library (which you get from a standard collection via .par
or by explicitly using classes from collection.parallel
) are pretty much guaranteed not to evaluate in order. If you want to be agnostic, you can use the GenX
set of traits (e.g. GenSeq
); these provide no guarantees either on execution order or that work will be done in parallel.
To complement the answer by Rex, foreach
at GenTraversableOnce
only guarantees all elements will be iterated through, unless you interrupt it. Traits lower on the hierarchy chain may provide additional guarantees, for example:
TraversableOnce
and descendants guarantee that only one element will be iterated through at a time (not guaranteed by GenTraversableOnce
!).Seq
and descendants guarantee that elements will be traversed on the order they are kept in the collection.And since you asked about parallel foreach
...
scala> (1 to 10).par foreach println
4
6
1
3
2
7
5
8
9
10
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