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Is event.currentTarget always equal to $(this) in jQuery?

Is this phrase always true?

$("p").click(function(event) {
  alert( event.currentTarget === this ); 
});  

Is one method preferred over the other? I like to use $(this) instead of event.currentTarget but can one do better in some conditions? Which is better? Are absolutely the same?

And another nuance - When checking on firebug console.log(this) and console.log($(this)) gives me exactly the same element. If they are the same - what is different? (since I know I can write this $(this).css('color','white') but can't write this.css('color','white')

like image 893
Alon Avatar asked Dec 22 '11 12:12

Alon


2 Answers

Generally, yes, it will be the same. You can make it different by using $.proxy to manipulate the context, but in practice you probably never will.

$(document.body).on('click', $.proxy(function(e) {
    console.log(this);            // window
    console.log(e.currentTarget); // document.body
}, window));

As to the other question, this is a native DOM element, whereas $(this) is a jQuery object wrapping that DOM element. The jQuery wrapper means you can run jQuery functions such as css, which are not available on native DOM elements.


And, to answer the precise wording of your question, event.currentTarget is normally equal to this, not to $(this).

like image 172
lonesomeday Avatar answered Sep 17 '22 20:09

lonesomeday


Part of your answer is above. I hope its clear enough.

No console.log(this) and console.log($j(this)) will not give you the same result. $(this) converts this to a jQuery Object and hence you can call .css like methods which can be called on jQuery objects($(this)) and not the HTML elements which will be this.

like image 45
Alok Swain Avatar answered Sep 19 '22 20:09

Alok Swain