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If I write:
int x = /* any non-zero integer value */;
float y = x;
float z = y / y;
Is z guaranteed to be exactly 1.f ?
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To divide float values in Python, use the / operator. The Division operator / takes two parameters and returns the float division. Float division produces a floating-point conjecture of the result of a division. If you are working with Python 3 and you need to perform a float division, then use the division operator.
If one of the operands in you division is a float and the other one is a whole number ( int , long , etc), your result's gonna be floating-point.
According to Python 3 documentation, Python when divided by integer, will generate float despite expected to be integer.
All Answers (9) Hope it will help! Carla, you have the answer in your question: 'any number divided by itself is equal to one' a zero is a number too, so 0/0 equals 1. Cheers!
If your C++ implementation uses IEEE754 then yes, this is guaranteed. (The division operator is required to return the best possible floating point value).
The only exceptions for y / y, in general, not being 1.f are the cases when y is NaN, +Inf, -Inf, 0.f, and -0.f, or if you are on a platform where int is so wide that certain instances of it cannot be represented in a float without that float being set to +Inf or -Inf1. Setting aside that final point, in your case that means that int x = 0; will produce the only exception.
IEEE754 is extremely common. But to check for sure, test the value of
std::numeric_limits<float>::is_iec559;
1A platform, for example, with a 128 bit int and an IEEE754 32 bit float would exhibit this behaviour for certain values of x.
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No, not in all cases, even for IEEE754.
For example, with int x = 0;, you'll get NaN. (Live)
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