I can't find anything to explain lost UITouch events. If you smash your full hand on the screen enough times, the number of touchesBegan will be different than the number of touchesEnded! I think the only way to actually know about these orphaned touches will be to reference them myself and keep track of how long they haven't moved.
Sample code:
int touchesStarted = 0;
int touchesFinished = 0;
- (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event
{
touchesStarted += touches.count;
}
- (void)touchesEnded:(NSSet *)touches withEvent:(UIEvent *)event
{
touchesFinished += touches.count;
NSLog(@"%d / %d", touchesStarted, touchesFinished);
}
- (void)touchesCancelled:(NSSet *)touches withEvent:(UIEvent *)event
{
[self touchesEnded:touches withEvent:event];
}
Don't forget about touchesCancelled
: UIResponder reference
Each touch object provides what phase it is in:
typedef enum {
UITouchPhaseBegan,
UITouchPhaseMoved,
UITouchPhaseStationary,
UITouchPhaseEnded,
UITouchPhaseCancelled,
} UITouchPhase;
I believe that if a touch starts and ends in the same touch event set, -touchesBegan:withEvent:
will be called but will contain touches which have ended or cancelled.
You should change your counting code, then, to look like this:
int touchesStarted = 0;
int touchesFinished = 0;
- (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event
{
[self customTouchHandler:touches];
}
- (void)touchesEnded:(NSSet *)touches withEvent:(UIEvent *)event
{
[self customTouchHandler:touches];
}
- (void)touchesCancelled:(NSSet *)touches withEvent:(UIEvent *)event
{
[self customTouchHandler:touches];
}
- (void)customTouchHandler:(NSSet *)touches
{
for(UITouch* touch in touches){
if(touch.phase == UITouchPhaseBegan)
touchesStarted++;
if(touch.phase == UITouchPhaseEnded || touch.phase == UITouchPhaseCancelled)
touchesFinished++;
}
NSLog(@"%d / %d", touchesStarted, touchesFinished);
}
Every single touch event will go through both phases of started and finished/cancelled, and so your counts should match up as soon as your fingers are off the screen.
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