I want to get a label's attributes from self so I tried:
UILabel *label = (UILabel *)[self viewWithTag:1];
But all I got was an empty UILabel instead of the label I was looking for. What is correct way to do this.
So I figured out what I was doing wrong. Obviously
UILabel *label = (UILabel *)[self viewWithTag:1];
creates a pointer to the instance of my label with tag 1. This does actually work. What doesn't work and why I was having problems came from trying to release label. Releasing label is the same as release [self viewWithTag:1] which is not what I was trying to do.
In Objective C for getting UILabel in UIViewController by tag.
here i take assumption as your UILabel
is added on self.view
, otherwise you can pass your view where you added UILabel
as [yourview viewWithTag:1];
UILabel *label = (UILabel *)[self.view viewWithTag:1];
In UITableView
UILabel *label = (UILabel *)[cell viewWithTag:1];
cell is a object of UITableViewCell
as
UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:@"Cell"];
In Swift 3
let label:UILabel = self.view.viewWithTag(1) as! UILabel
In UITableView
let cell:UITableViewCell = self.tableView.dequeueReusableCell(withIdentifier: "Cell") as UITableViewCell! let label:UILabel = cell.viewWithTag(1) as! UILabel
NOTE: before using tag (viewWithTag) there should be object (UILabel) with that tag number, otherwise app is crash.
you can set tag for any object via storyboard or via XIB and programatically.
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