I am trying to access items in an array of structs and print the structs fields as follows
printList(Album *a, int numOfStructs)
{
int i;
int j;
for(i = 0; i < numOfStructs; i++)
{
printf("number%d\n:", i+1);
printf("%s", a[i]->field2);
printf("%s", a[i]->field2);
printf("%d", a[i]->field3);
for(j = 0; j < a[i]->numOfStrings; j++)
{
printf("%s", a[i]->strings[j]);
}
printf("\n");
}
}
but I get loads of errors as such
invalid type argument of '->'
What am I doing wrong with this pointer?
a
is of type Album*
which means that a[i]
is of type Album
(it is the i
th element in the array of Album
object pointed to by a
).
The left operand of ->
must be a pointer; the .
operator is used if it is not a pointer.
You need to use the .
operator. You see, when you apply a *
to a pointer, you are dereferencing it. The same goes with the []
. The difference between *
and []
is that the brackets require an offset from the pointer, which is added to the address in the pointer, before it is dereferenced. Basically, these expressions are identical:
*ptr == ptr[0]
*(ptr + 1) == ptr[1]
*(ptr + 2) == ptr[2]
To connect to your question: Change a[i]->field2
and a[i]->field3
to a[i].field2
and a[i].field3
.
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