Interpreting GPS info of exif data from photo in python

Question

I am writing a small program to get the GPS info of a iphone jpg photo.

The library I am using is the PIL in python. Now I am able to get the GPSInfo, which is something like:

{1: 'N', 
 2: ((1, 1), (20, 1), (5365, 100)), 
 3: 'E', 
 4: ((103, 1), (41, 1), (1052, 100)), 
 5: 0, 
 6: (43, 1), 
 7: ((15, 1), (32, 1), (7, 1)), 
 16: 'T', 
 17: (77473, 452), 
 29: '2013:10:25'}

How can I interpret this? And I notice the tag is not continuous, so is there any cheating sheet which I can refer to in order to get a better understanding of all the number tags and what they mean? Thank you!

UPDATES

Sorry, I have figured it out. In the PIL lib, there is a GPSTAGS.get() function which can help me decode the key in gps info. Thank you guys!

gpsinfo = {}
for key in exif['GPSInfo'].keys():
    decode = ExifTags.GPSTAGS.get(key,key)
    gpsinfo[decode] = exif['GPSInfo'][key]
print gpsinfo

and here is the result

{'GPSTimeStamp': ((15, 1), (32, 1), (7, 1)), 
 'GPSImgDirectionRef': 'T', 
 'GPSImgDirection': (77473, 452), 
 'GPSLongitude': ((103, 1), (41, 1), (1052, 100)), 
 'GPSLatitudeRef': 'N', 29: '2013:10:25', 
 'GPSAltitude': (43, 1), 
 'GPSLatitude': ((1, 1), (20, 1), (5365, 100)), 
 'GPSLongitudeRef': 'E', 
 'GPSAltitudeRef': 0}

Answer 1

Use exifread module.

Here is a very helpful gist

import exifread as ef   # barrowed from  # https://gist.github.com/snakeye/fdc372dbf11370fe29eb  def _convert_to_degress(value):     """     Helper function to convert the GPS coordinates stored in the EXIF to degress in float format     :param value:     :type value: exifread.utils.Ratio     :rtype: float     """     d = float(value.values[0].num) / float(value.values[0].den)     m = float(value.values[1].num) / float(value.values[1].den)     s = float(value.values[2].num) / float(value.values[2].den)      return d + (m / 60.0) + (s / 3600.0)   def getGPS(filepath):     '''     returns gps data if present other wise returns empty dictionary     '''     with open(filepath, 'rb') as f:         tags = ef.process_file(f)         latitude = tags.get('GPS GPSLatitude')         latitude_ref = tags.get('GPS GPSLatitudeRef')         longitude = tags.get('GPS GPSLongitude')         longitude_ref = tags.get('GPS GPSLongitudeRef')         if latitude:             lat_value = _convert_to_degress(latitude)             if latitude_ref.values != 'N':                 lat_value = -lat_value         else:             return {}         if longitude:             lon_value = _convert_to_degress(longitude)             if longitude_ref.values != 'E':                 lon_value = -lon_value         else:             return {}         return {'latitude': lat_value, 'longitude': lon_value}     return {}   file_path = 'file path of the file'     gps = getGPS(file_path) print gps                        

Answer 2

Late answer, but as of 2021 you can use GPSPhoto, i.e.:

from GPSPhoto import gpsphoto # Get the data from image file and return a dictionary data = gpsphoto.getGPSData('IMG_20181224_201933.jpg') print(data['Latitude'], data['Longitude']) 

---

Output:

38.71615498471598 -9.148730635643007

---

Installation:

pip3 install piexif pip3 install gpsphoto 

Answer 3

OP, has already posted a solution using PIL. If you wants to just get GPS info from Python, you can get it by using exifread

Install package using pip

$ pip install exifread

and get GPS data

In [10]: import exifread

In [11]: tags = exifread.process_file(open('./tests/demo-project/content/test.jpg', 'rb'))                                              

In [12]: geo = {i:tags[i] for i in tags.keys() if i.startswith('GPS')}

In [13]: geo
Out[13]: 
{'GPS GPSAltitude': (0x0006) Ratio=186188/239 @ 898,
 'GPS GPSAltitudeRef': (0x0005) Byte=0 @ 722,
 'GPS GPSDate': (0x001D) ASCII=2015:12:06 @ 954,
 'GPS GPSDestBearing': (0x0018) Ratio=43771/526 @ 946,
 'GPS GPSDestBearingRef': (0x0017) ASCII=T @ 806,
 'GPS GPSImgDirection': (0x0011) Ratio=43771/526 @ 938,
 'GPS GPSImgDirectionRef': (0x0010) ASCII=T @ 782,
 'GPS GPSLatitude': (0x0002) Ratio=[46, 3803/100, 0] @ 850,
 'GPS GPSLatitudeRef': (0x0001) ASCII=N @ 674,
 'GPS GPSLongitude': (0x0004) Ratio=[13, 2429/100, 0] @ 874,
 'GPS GPSLongitudeRef': (0x0003) ASCII=E @ 698,
 'GPS GPSSpeed': (0x000D) Ratio=139/50 @ 930,
 'GPS GPSSpeedRef': (0x000C) ASCII=K @ 758,
 'GPS GPSTimeStamp': (0x0007) Ratio=[10, 37, 33] @ 906,
 'GPS Tag 0x001F': (0x001F) Ratio=30 @ 966}