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Interpolate function using Apache Commons Math

I'm trying to implement some Interpolation functions to plot some values where the X value = Date.seconds and the Y value = double.

I'v been researching using the Apache Commons Math lib to achieve this and I've found a method I think I might be able to use here

The method I'm trying to understand:

public double linearInterp(double[] x, double[] y, double xi) {
   // return linear interpolation of (x,y) on xi
   LinearInterpolator li = new LinearInterpolator();
   PolynomialSplineFunction psf = li.interpolate(x, y);
   double yi = psf.value(xi);
   return yi;
}

I don't understand where I'm supposed to get the xi value from?

What is xi what value do I pass into this method for xi, am I supposed to loop through my array of X values and pass in the ith element of X with the array of X and Y?

And when I want to plot this new data do I use the returned yi along with the passed in xi to plot?

like image 912
JTK Avatar asked Apr 09 '16 22:04

JTK


1 Answers

The interpolate method expects arrays of pairs (here called x and y) and returns a function (psf) that fits these values as best as possible.

This function is then used to interpolate the yi-value of a given xi-value (which is normally not contained in the x/y array used to define the function).

So you have pairs containing of x- and y-values defining a function and use this function to interpolate missing values.

See the userguide on Apache Commons (Chapter 4.4: Interpolation).


Example:

badly drawn example of a spline interpolation

The green dots are known value pairs. These are defined by the x and y value arrays.

When calling interpolate, the returned PolynomialSplineFunction returns the function that is approximated using the known value pairs. The shape of the funtion is defined by the type of UnivariateInterpolator that is used. In the question example, a LinearInterpolator is used. The drawing shows the function returned by a spline interpolator.

The red dot symbolizes a value with an unknown y-value on the interpolated function (this would be the value with an x-value of xi in the question example).

If you need to calculate more than one extra value, use a function like this

public double[] linearInterp(double[] x, double[] y, double[] xi) {
   LinearInterpolator li = new LinearInterpolator(); // or other interpolator
   PolynomialSplineFunction psf = li.interpolate(x, y);

   double[] yi = new double[xi.length];
   for (int i = 0; i < xi.length; i++) {
       yi[i] = psf.value(xi[i]);
   }
   return yi;
}

A calculation example:

public class Interpolate {

    public static void main(String[] args) {
        double[] x = { 0, 50, 100 };
        double[] y = { 0, 50, 200 };

        LinearInterpolator interp = new LinearInterpolator();
        PolynomialSplineFunction f = interp.interpolate(x, y);

        System.out.println("Piecewise functions:");
        Arrays.stream(f.getPolynomials()).forEach(System.out::println);

        double value = f.value(70);
        System.out.println("y for xi = 70: " + value);
    }
}

Three known value pairs are given:

(0, 0)
(50, 50)
(100, 200)

One value is unknown:

(70, ?)

The LinearInterpolator interpolates the given values and generates a function with two piecewise, linear polynomials:

y = x             (for x values < 50)
y = 50 + 3 * x    (for x-values >= 50)

The value of the interpolated xi (here: 70) is

y = 50 + 3 * (70 - 50) = 110
like image 167
Modus Tollens Avatar answered Sep 22 '22 07:09

Modus Tollens