Integer to IP Address - C

Question

I'm preparing for a quiz, and I have a strong suspicion I may be tasked with implementing such a function. Basically, given an IP address in network notation, how can we get that from a 32 bit integer into a string in it's dotted decimal notation (something like 155.247.182.83)...? Obviously we can't be using any type of inet functions either...I'm stumped!

Answer 1

Here's a simple method to do it: The (ip >> 8), (ip >> 16) and (ip >> 24) moves the 2nd, 3rd and 4th bytes into the lower order byte, while the & 0xFF isolates the least significant byte at each step.

void print_ip(unsigned int ip) {     unsigned char bytes[4];     bytes[0] = ip & 0xFF;     bytes[1] = (ip >> 8) & 0xFF;     bytes[2] = (ip >> 16) & 0xFF;     bytes[3] = (ip >> 24) & 0xFF;        printf("%d.%d.%d.%d\n", bytes[3], bytes[2], bytes[1], bytes[0]);         } 

There is an implied bytes[0] = (ip >> 0) & 0xFF; at the first step.

Use snprintf() to print it to a string.

Answer 2

You actually can use an inet function. Observe.

main.c:

#include <arpa/inet.h>  main() {     uint32_t ip = 2110443574;     struct in_addr ip_addr;     ip_addr.s_addr = ip;     printf("The IP address is %s\n", inet_ntoa(ip_addr)); } 

The results of gcc main.c -ansi; ./a.out is

The IP address is 54.208.202.125

Note that a commenter said this does not work on Windows.