Menu
Possible Duplicate:
Varying behavior for possible loss of precision
int testing = 0;
testing += 2.0
the above code compiles.
where as
int testing = 0;
testing = testing + 2.0;
this code doesn't compile. Any idea why?
645
We can convert int to double in java using assignment operator. There is nothing to do extra because lower type can be converted to higher type implicitly. It is also known as implicit type casting or type promotion.
As we all know, a Double primitive contains decimal digits. On conversion of these values to integers, the decimal digits get truncated, by rounding off the number to the nearest integer according to the method you choose. Java provides the following three ways to convert Double values to integer numbers: TypeCasting.
The values of int data type and double data type will be printed through the C++ cout command. Before assigning the int value to the double variable, the compiler transforms it to double automatically.
Compound assignment has a hidden cast in Java.
A compound assignment expression of the form E1 op= E2 is equivalent to E1 = (T)((E1) op (E2)), where T is the type of E1, except that E1 is evaluated only once.
For example, the following code is correct:
short x = 3; x += 4.6;and results in
xhaving the value7because it is equivalent to:short x = 3; x = (short)(x + 4.6);
192
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
