Instantiating Array and Instantiating each Member at once

Question

Consider the following case:

ColumnDefinition[] columns = new ColumnDefinition[2];
columns[0] = new ColumnDefinition();
columns[1] = new ColumnDefinition();

After instantiating columns as an array of ColumnDefinition, I needed to explicitly instantiate each array element. Of course, it could have been done using loops, but I was wondering if there was something simpler which would instantiate every element at once after instantiating the Array type itself.

Answer 1

You can apply a little LINQ:

var columns = Enumerable.Repeat(new ColumnDefinition(), 10).ToArray();

Adjust the count passed to Repeat for the size of array. However this will lead to the same object being saved in each element of the array. So maybe the creation needs to be repeated:

var columns = Enumerable.Repeat(0, 10).Select(i => new ColumnDefinition()).ToArray();

Answer 2

var columns = new []{new ColumnDefinition(), new ColumnDefinition()};

Works as expected.