You can use advanced string formatting, available in Python 2.6 and Python 3.x:
incoming = 'arbit'
result = '{0} hello world {0} hello world {0}'.format(incoming)
incoming = 'arbit'
result = '%(s)s hello world %(s)s hello world %(s)s' % {'s': incoming}
You may like to have a read of this to get an understanding: String Formatting Operations.
You can use the dictionary type of formatting:
s='arbit'
string='%(key)s hello world %(key)s hello world %(key)s' % {'key': s,}
Depends on what you mean by better. This works if your goal is removal of redundancy.
s='foo'
string='%s bar baz %s bar baz %s bar baz' % (3*(s,))
>>> s1 ='arbit'
>>> s2 = 'hello world '.join( [s]*3 )
>>> print s2
arbit hello world arbit hello world arbit
If you are using Python 3.6+
you can make use of the new so called f-strings
which stands for formatted strings and it can be used by adding the character f
at the beginning of a string to identify this as an f-string.
price = 123
name = "Jerry"
print(f"{name}!!, {price} is much, isn't {price} a lot? {name}!")
>Jerry!!, 123 is much, isn't 123 a lot? Jerry!
The main benefits of using f-strings is that they are more readable, can be faster, and offer better performance:
Source Pandas for Everyone: Python Data Analysis, By Daniel Y. Chen
No doubt that the new f-strings
are more readable, as you don't have to remap the strings, but is it faster though as stated in the aformentioned quote?
price = 123
name = "Jerry"
def new():
x = f"{name}!!, {price} is much, isn't {price} a lot? {name}!"
def old():
x = "{1}!!, {0} is much, isn't {0} a lot? {1}!".format(price, name)
import timeit
print(timeit.timeit('new()', setup='from __main__ import new', number=10**7))
print(timeit.timeit('old()', setup='from __main__ import old', number=10**7))
> 3.8741058271543776 #new
> 5.861819514350163 #old
Running 10 Million test's it seems that the new f-strings
are actually faster in mapping.
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