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I'm trying to insert one byte array into another at the beginning. Here's a simple example of what I'm trying to accomplish.
import struct
a = bytearray(struct.pack(">i", 1))
b = bytearray(struct.pack(">i", 2))
a = a.insert(0, b)
print(a)
However this fails with the following error:
a = a.insert(0, b)
TypeError: an integer is required
412
Python | bytearray() functionbytearray() method returns a bytearray object which is an array of given bytes. It gives a mutable sequence of integers in the range 0 <= x < 256. Returns: Returns an array of bytes of the given size. source parameter can be used to initialize the array in few different ways.
To join a list of Bytes, call the Byte. join(list) method. If you try to join a list of Bytes on a string delimiter, Python will throw a TypeError , so make sure to call it on a Byte object b' '. join(...)
Python bytearray() Function The bytearray() function returns a bytearray object. It can convert objects into bytearray objects, or create empty bytearray object of the specified size.
bytearray is a sequence-type, and it supports slice-based operations. The "insert at position i" idiom with slices goes like this x[i:i] = <a compatible sequence>. So, for the fist position:
>>> a
bytearray(b'\x00\x00\x00\x01')
>>> b
bytearray(b'\x00\x00\x00\x02')
>>> a[0:0] = b
>>> a
bytearray(b'\x00\x00\x00\x02\x00\x00\x00\x01')
For the third position:
>>> a
bytearray(b'\x00\x00\x00\x01')
>>> b
bytearray(b'\x00\x00\x00\x02')
>>> a[2:2] = b
>>> a
bytearray(b'\x00\x00\x00\x00\x00\x02\x00\x01')
Note, this isn't equivalent to .insert, because for sequences, .insert inserts the entire object as the ith element. So, consider the following simple example with lists:
>>> y = ['a','b']
>>> x.insert(0, y)
>>>
>>> x
[['a', 'b'], 1, 2, 3]
What you really wanted was:
>>> x
[1, 2, 3]
>>> y
['a', 'b']
>>> x[0:0] = y
>>> x
['a', 'b', 1, 2, 3]
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