Initialize Objects like arrays in PHP?

Question

In PHP, you can initialize arrays with values quickly using the following notation:

$array = array("name" => "member 1", array("name" => "member 1.1") ) .... 

is there any way to do this for STDClass objects? I don't know any shorter way than the dreary

$object = new STDClass(); $object->member1 = "hello, I'm 1"; $object->member1->member1 = "hello, I'm 1.1"; $object->member2 = "hello, I'm 2"; 

Answer 1

You can use type casting:

$object = (object) array("name" => "member 1", array("name" => "member 1.1") ); 

Answer 2

I also up-voted Gumbo as the preferred solution but what he suggested is not exactly what was asked, which may lead to some confusion as to why member1o looks more like a member1a.

To ensure this is clear now, the two ways (now 3 ways since 5.4) to produce the same stdClass in php.

1. As per the question's long or manual approach:

   $object = new stdClass; $object->member1 = "hello, I'm 1"; $object->member1o = new stdClass; $object->member1o->member1 = "hello, I'm 1o.1"; $object->member2 = "hello, I'm 2"; 

2. The shorter or single line version (expanded here for clarity) to cast an object from an array, ala Gumbo's suggestion.

   $object = (object)array(      'member1' => "hello, I'm 1",      'member1o' => (object)array(          'member1' => "hello, I'm 1o.1",      ),      'member2' => "hello, I'm 2", ); 

3. PHP 5.4+ Shortened array declaration style

   $object = (object)[      'member1' => "hello, I'm 1",      'member1o' => (object)['member1' => "hello, I'm 1o.1"],      'member2' => "hello, I'm 2", ]; 

Will both produce exactly the same result:

stdClass Object (     [member1] => hello, I'm 1     [member1o] => stdClass Object         (             [member1] => hello, I'm 1o.1         )      [member2] => hello, I'm 2 ) 

nJoy!