Initialize member before base constructor. Possible? [duplicate]

Question

I have the following code:

class A{
public:
    A(int* i){
        std::cout << "in A()" << i << std::endl;
    }
};

class B: public A{
public:
    B(): i{new int{10}}, A{i}{
        std::cout << "in B()" << std::endl; 
    }

private:
    int* i;
};

int main()
{
    B b;
}

In A constructor I have 0 (which is expected). But I want to initialize i before. Is it possible at all?

Answer 1

i is a data member of class B, so in order to be created, an object of class B has to be created first. So the answer, is no.